A container holding 6.75 liters of water is to be used to fill as many

Praxis 5003 Practice Test

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Question 1 of 5.

A container holding 6.75 liters of water is to be used to fill as many 225-milliliter plastic water bottles as possible. How many 225-milliliter bottles can be filled?

A. 40

B. 35

C. 30

D. 25

Explanation: Convert liters to milliliters: 6.75 L = 6750 mL. Number of bottles = 6750 / 225 = 30. Option A is 40, which is too high. Option B is 35, still high. Option D is 25, too low.

Question 2 of 5.

Which of the following is an equation?

A. x = 2

B. xÂ²+xy-y

C. 3x - 4 = 20y^2

D. 13y = y + 1

E. x/5 = 9

Explanation: An equation is a statement that two expressions are equal, containing an equals sign. x=2 is an equation. xÂ²+xy-y is an expression, not an equation. 3x-4=20y^2 is an equation. 13y=y+1 is an equation. x/5=9 is an equation. Therefore, the equations are A, C, D, and E.

Question 3 of 5.

Which of the following best describes the expression shown?

A. The expression has two terms, none of which are constants.

B. The expression has two terms, one of which is a constant.

C. The expression has three terms, one of which is a constant.

D. The expression has three terms, all of which are constants.

Explanation: The expression has three terms: 5xÂ², 2x, and -2. The term -2 is a constant. Option A is incorrect because there are three terms and one is a constant. Option B is wrong as there are three terms. Option D is incorrect because not all terms are constants; 5xÂ² and 2x are variable terms.

Question 4 of 5.

Which of the following lists contains all the coefficients of the expression 12x^3 + 7x^2 + 24x?

A. 2, 3

B. 7, 12

C. 7, 12, 24

D. 2, 3, 7, 12, 24

Explanation: Coefficients are the numerical factors of the terms. For 12xÂ³, the coefficient is 12; for 7xÂ², it is 7; for 24x, it is 24. So the coefficients are 12, 7, and 24. Option A lists digits from the exponents. Option B misses 24. Option D includes digits that are not coefficients.

Question 5 of 5.

In terms of x, what is the sum of the lengths of the sides of the preceding polygon?

A. 18x-22

B. 21x-5

C. 23x+32

D. 19x-2

Explanation: To find the sum of the lengths of the sides of the polygon, we first identify the given side lengths: AB = 10- 2x, BC = x+3, CD=4x-5, DE = 6x-7, EF = 62-5, and FA = 42 +2. Next, we add these expressions together: (10-2)+(x+3)+(4x-5)+(6x-7)+(6x-5)+(4x+2). Combining like terms, we group all coefficients of a and constant values: (-2x+x+4x+6x+6x+ 4x)+(10+3-5-7-5+2). Simplifying further, the coefficient of adds up to 192, while the constants simplify to -2. Therefore, the total sum of the lengths of all the sides of the polygon is 19 - 2. This expression represents the perimeter of the polygon in terms of 2.